Base | Representation |
---|---|
bin | 10111011001010100… |
… | …111100000100100011 |
3 | 2101211201120001221012 |
4 | 113121110330010203 |
5 | 402421432400113 |
6 | 15312421451135 |
7 | 1546343550326 |
oct | 273124740443 |
9 | 71751501835 |
10 | 25120981283 |
11 | a721159062 |
12 | 4a50b70aab |
13 | 24a4614c88 |
14 | 130447a7bd |
15 | 9c061daa8 |
hex | 5d953c123 |
25120981283 has 2 divisors, whose sum is σ = 25120981284. Its totient is φ = 25120981282.
The previous prime is 25120981279. The next prime is 25120981289. The reversal of 25120981283 is 38218902152.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25120981283 - 22 = 25120981279 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25120981283.
It is not a weakly prime, because it can be changed into another prime (25120981289) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12560490641 + 12560490642.
It is an arithmetic number, because the mean of its divisors is an integer number (12560490642).
Almost surely, 225120981283 is an apocalyptic number.
25120981283 is a deficient number, since it is larger than the sum of its proper divisors (1).
25120981283 is an equidigital number, since it uses as much as digits as its factorization.
25120981283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 41.
The spelling of 25120981283 in words is "twenty-five billion, one hundred twenty million, nine hundred eighty-one thousand, two hundred eighty-three".
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