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25120981283 is a prime number
BaseRepresentation
bin10111011001010100…
…111100000100100011
32101211201120001221012
4113121110330010203
5402421432400113
615312421451135
71546343550326
oct273124740443
971751501835
1025120981283
11a721159062
124a50b70aab
1324a4614c88
14130447a7bd
159c061daa8
hex5d953c123

25120981283 has 2 divisors, whose sum is σ = 25120981284. Its totient is φ = 25120981282.

The previous prime is 25120981279. The next prime is 25120981289. The reversal of 25120981283 is 38218902152.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25120981283 - 22 = 25120981279 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25120981283.

It is not a weakly prime, because it can be changed into another prime (25120981289) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12560490641 + 12560490642.

It is an arithmetic number, because the mean of its divisors is an integer number (12560490642).

Almost surely, 225120981283 is an apocalyptic number.

25120981283 is a deficient number, since it is larger than the sum of its proper divisors (1).

25120981283 is an equidigital number, since it uses as much as digits as its factorization.

25120981283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 41.

The spelling of 25120981283 in words is "twenty-five billion, one hundred twenty million, nine hundred eighty-one thousand, two hundred eighty-three".