Base | Representation |
---|---|
bin | 100100100011100111111… |
… | …011010111011000011111 |
3 | 22220011022012012010101211 |
4 | 210203213323113120133 |
5 | 312124341403000111 |
6 | 5202022223445251 |
7 | 346332316451062 |
oct | 44434773273037 |
9 | 8804265163354 |
10 | 2512152000031 |
11 | 889441348813 |
12 | 346a56756827 |
13 | 152b83195cbb |
14 | 8983597a8d9 |
15 | 455308a8521 |
hex | 248e7ed761f |
2512152000031 has 2 divisors, whose sum is σ = 2512152000032. Its totient is φ = 2512152000030.
The previous prime is 2512151999993. The next prime is 2512152000047. The reversal of 2512152000031 is 1300002512152.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2512152000031 - 211 = 2512151997983 is a prime.
It is a super-2 number, since 2×25121520000312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2512151999966 and 2512152000011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2512152007031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256076000015 + 1256076000016.
It is an arithmetic number, because the mean of its divisors is an integer number (1256076000016).
Almost surely, 22512152000031 is an apocalyptic number.
2512152000031 is a deficient number, since it is larger than the sum of its proper divisors (1).
2512152000031 is an equidigital number, since it uses as much as digits as its factorization.
2512152000031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 600, while the sum is 22.
Adding to 2512152000031 its reverse (1300002512152), we get a palindrome (3812154512183).
The spelling of 2512152000031 in words is "two trillion, five hundred twelve billion, one hundred fifty-two million, thirty-one", and thus it is an aban number.
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