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251242251324013 is a prime number
BaseRepresentation
bin111001001000000011100101…
…001001001000101001101101
31012221120112011110211002011001
4321020003211021020221231
5230412323112314332023
62250203032532000301
7103630440126052435
oct7110034511105155
91187515143732131
10251242251324013
1173065271000624
1224218521760091
13aa260728b06a1
144608292d212c5
151e0a5c2d7a6ad
hexe480e5248a6d

251242251324013 has 2 divisors, whose sum is σ = 251242251324014. Its totient is φ = 251242251324012.

The previous prime is 251242251324007. The next prime is 251242251324061. The reversal of 251242251324013 is 310423152242152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133737128283529 + 117505123040484 = 11564477^2 + 10839978^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-251242251324013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251242251324313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125621125662006 + 125621125662007.

It is an arithmetic number, because the mean of its divisors is an integer number (125621125662007).

Almost surely, 2251242251324013 is an apocalyptic number.

It is an amenable number.

251242251324013 is a deficient number, since it is larger than the sum of its proper divisors (1).

251242251324013 is an equidigital number, since it uses as much as digits as its factorization.

251242251324013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 37.

The spelling of 251242251324013 in words is "two hundred fifty-one trillion, two hundred forty-two billion, two hundred fifty-one million, three hundred twenty-four thousand, thirteen".