Base | Representation |
---|---|
bin | 1110100111111101010… |
… | …0100111001100110001 |
3 | 220000111122022102112202 |
4 | 3221333110213030301 |
5 | 13104022004304131 |
6 | 311230415232545 |
7 | 24103031401013 |
oct | 3517724471461 |
9 | 800448272482 |
10 | 251244213041 |
11 | 97608898998 |
12 | 40839218755 |
13 | 1a8cca93723 |
14 | c235b701b3 |
15 | 6807189bcb |
hex | 3a7f527331 |
251244213041 has 2 divisors, whose sum is σ = 251244213042. Its totient is φ = 251244213040.
The previous prime is 251244213019. The next prime is 251244213049. The reversal of 251244213041 is 140312442152.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 226823587600 + 24420625441 = 476260^2 + 156271^2 .
It is a cyclic number.
It is not a de Polignac number, because 251244213041 - 222 = 251240018737 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251244212995 and 251244213013.
It is not a weakly prime, because it can be changed into another prime (251244213049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125622106520 + 125622106521.
It is an arithmetic number, because the mean of its divisors is an integer number (125622106521).
Almost surely, 2251244213041 is an apocalyptic number.
It is an amenable number.
251244213041 is a deficient number, since it is larger than the sum of its proper divisors (1).
251244213041 is an equidigital number, since it uses as much as digits as its factorization.
251244213041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 29.
Adding to 251244213041 its reverse (140312442152), we get a palindrome (391556655193).
The spelling of 251244213041 in words is "two hundred fifty-one billion, two hundred forty-four million, two hundred thirteen thousand, forty-one".
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