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25130023843 is a prime number
BaseRepresentation
bin10111011001110111…
…011011101110100011
32101212100120110222211
4113121313123232203
5402431241230333
615313343342551
71546513451431
oct273167335643
971770513884
1025130023843
11a726274951
124a53bb1a57
1324a645cac2
141305751d51
159c1307ecd
hex5d9ddbba3

25130023843 has 2 divisors, whose sum is σ = 25130023844. Its totient is φ = 25130023842.

The previous prime is 25130023771. The next prime is 25130023871. The reversal of 25130023843 is 34832003152.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25130023843 - 217 = 25129892771 is a prime.

It is not a weakly prime, because it can be changed into another prime (25130023943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565011921 + 12565011922.

It is an arithmetic number, because the mean of its divisors is an integer number (12565011922).

Almost surely, 225130023843 is an apocalyptic number.

25130023843 is a deficient number, since it is larger than the sum of its proper divisors (1).

25130023843 is an equidigital number, since it uses as much as digits as its factorization.

25130023843 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 25130023843 its reverse (34832003152), we get a palindrome (59962026995).

The spelling of 25130023843 in words is "twenty-five billion, one hundred thirty million, twenty-three thousand, eight hundred forty-three".