Base | Representation |
---|---|
bin | 10111011001110111… |
… | …011011101110100011 |
3 | 2101212100120110222211 |
4 | 113121313123232203 |
5 | 402431241230333 |
6 | 15313343342551 |
7 | 1546513451431 |
oct | 273167335643 |
9 | 71770513884 |
10 | 25130023843 |
11 | a726274951 |
12 | 4a53bb1a57 |
13 | 24a645cac2 |
14 | 1305751d51 |
15 | 9c1307ecd |
hex | 5d9ddbba3 |
25130023843 has 2 divisors, whose sum is σ = 25130023844. Its totient is φ = 25130023842.
The previous prime is 25130023771. The next prime is 25130023871. The reversal of 25130023843 is 34832003152.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25130023843 - 217 = 25129892771 is a prime.
It is not a weakly prime, because it can be changed into another prime (25130023943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565011921 + 12565011922.
It is an arithmetic number, because the mean of its divisors is an integer number (12565011922).
Almost surely, 225130023843 is an apocalyptic number.
25130023843 is a deficient number, since it is larger than the sum of its proper divisors (1).
25130023843 is an equidigital number, since it uses as much as digits as its factorization.
25130023843 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 25130023843 its reverse (34832003152), we get a palindrome (59962026995).
The spelling of 25130023843 in words is "twenty-five billion, one hundred thirty million, twenty-three thousand, eight hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •