25131142111 has 4 divisors (see below), whose sum is σ = 25131459232. Its totient is φ = 25130824992.

The previous prime is 25131142033. The next prime is 25131142121. The reversal of 25131142111 is 11124113152.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 25131142111 - 2⁷ = 25131141983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25131142121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74506 + ... + 236248.

It is an arithmetic number, because the mean of its divisors is an integer number (6282864808).

Almost surely, 2^25131142111 is an apocalyptic number.

25131142111 is a deficient number, since it is larger than the sum of its proper divisors (317121).

25131142111 is a wasteful number, since it uses less digits than its factorization.

25131142111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 317120.

The product of its digits is 240, while the sum is 22.

Adding to 25131142111 its reverse (11124113152), we get a palindrome (36255255263).

The spelling of 25131142111 in words is "twenty-five billion, one hundred thirty-one million, one hundred forty-two thousand, one hundred eleven".