Base | Representation |
---|---|
bin | 1110101000010110100… |
… | …0001011000101001001 |
3 | 220000210000101011111221 |
4 | 3222011220023011021 |
5 | 13104231100112131 |
6 | 311245114522041 |
7 | 24105454532413 |
oct | 3520550130511 |
9 | 800700334457 |
10 | 251350004041 |
11 | 97662585274 |
12 | 40868736321 |
13 | 1a918984056 |
14 | c245c2b9b3 |
15 | 68115d5411 |
hex | 3a85a0b149 |
251350004041 has 2 divisors, whose sum is σ = 251350004042. Its totient is φ = 251350004040.
The previous prime is 251350004027. The next prime is 251350004089. The reversal of 251350004041 is 140400053152.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 225430292025 + 25919712016 = 474795^2 + 160996^2 .
It is a cyclic number.
It is not a de Polignac number, because 251350004041 - 223 = 251341615433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 251350003997 and 251350004015.
It is not a weakly prime, because it can be changed into another prime (251350004021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125675002020 + 125675002021.
It is an arithmetic number, because the mean of its divisors is an integer number (125675002021).
Almost surely, 2251350004041 is an apocalyptic number.
It is an amenable number.
251350004041 is a deficient number, since it is larger than the sum of its proper divisors (1).
251350004041 is an equidigital number, since it uses as much as digits as its factorization.
251350004041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2400, while the sum is 25.
Adding to 251350004041 its reverse (140400053152), we get a palindrome (391750057193).
The spelling of 251350004041 in words is "two hundred fifty-one billion, three hundred fifty million, four thousand, forty-one".
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