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25140803 is a prime number
BaseRepresentation
bin101111111100…
…1111001000011
31202022021200212
41133321321003
522414001203
62254504335
7423456542
oct137717103
952267625
1025140803
1113211726
1285050ab
13529331c
1434a6159
1523191d8
hex17f9e43

25140803 has 2 divisors, whose sum is σ = 25140804. Its totient is φ = 25140802.

The previous prime is 25140799. The next prime is 25140823. The reversal of 25140803 is 30804152.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25140803 - 22 = 25140799 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (25140823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12570401 + 12570402.

It is an arithmetic number, because the mean of its divisors is an integer number (12570402).

Almost surely, 225140803 is an apocalyptic number.

25140803 is a deficient number, since it is larger than the sum of its proper divisors (1).

25140803 is an equidigital number, since it uses as much as digits as its factorization.

25140803 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

The square root of 25140803 is about 5014.0605301492. The cubic root of 25140803 is about 292.9496937476.

Adding to 25140803 its reverse (30804152), we get a palindrome (55944955).

The spelling of 25140803 in words is "twenty-five million, one hundred forty thousand, eight hundred three".