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25145000131 = 115811217121
BaseRepresentation
bin10111011010110000…
…100100000011000011
32101220101202100121011
4113122300210003003
5402444110001011
615315040341351
71550054655166
oct273260440303
971811670534
1025145000131
11a733773849
124a59014857
1324a95a4704
14130772dadd
159c27b5621
hex5dac240c3

25145000131 has 4 divisors (see below), whose sum is σ = 25145333064. Its totient is φ = 25144667200.

The previous prime is 25145000113. The next prime is 25145000173. The reversal of 25145000131 is 13100054152.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 25145000131 - 213 = 25144991939 is a prime.

It is a super-2 number, since 2×251450001312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25145000191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7251 + ... + 224371.

It is an arithmetic number, because the mean of its divisors is an integer number (6286333266).

Almost surely, 225145000131 is an apocalyptic number.

25145000131 is a deficient number, since it is larger than the sum of its proper divisors (332933).

25145000131 is a wasteful number, since it uses less digits than its factorization.

25145000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 332932.

The product of its (nonzero) digits is 600, while the sum is 22.

Adding to 25145000131 its reverse (13100054152), we get a palindrome (38245054283).

The spelling of 25145000131 in words is "twenty-five billion, one hundred forty-five million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 115811 217121 25145000131