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25145004112153 = 147703917023927
BaseRepresentation
bin1011011011110100001110…
…00010011011100100011001
310022000211122120101202012021
411231322013002123210121
511243433432023042103
6125251242212014441
75203444433265442
oct555720702334431
9108024576352167
1025145004112153
118014a33324212
1229a132b001421
1311052188a84a3
1462d04ba842c9
152d912c793bbd
hex16de8709b919

25145004112153 has 4 divisors (see below), whose sum is σ = 25145022613120. Its totient is φ = 25144985611188.

The previous prime is 25145004112141. The next prime is 25145004112237. The reversal of 25145004112153 is 35121140054152.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25145004112153 - 29 = 25145004111641 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25145004110153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7034925 + ... + 9989002.

It is an arithmetic number, because the mean of its divisors is an integer number (6286255653280).

Almost surely, 225145004112153 is an apocalyptic number.

It is an amenable number.

25145004112153 is a deficient number, since it is larger than the sum of its proper divisors (18500967).

25145004112153 is a wasteful number, since it uses less digits than its factorization.

25145004112153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18500966.

The product of its (nonzero) digits is 24000, while the sum is 34.

The spelling of 25145004112153 in words is "twenty-five trillion, one hundred forty-five billion, four million, one hundred twelve thousand, one hundred fifty-three".

Divisors: 1 1477039 17023927 25145004112153