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2520130001 = 11743214607
BaseRepresentation
bin1001011000110110…
…0010000111010001
320111122001212110012
42112031202013101
520130123130001
61054023044305
7116310515534
oct22615420721
96448055405
102520130001
111083602a74
125a3ba0695
13312159aac
1419c9b0a1b
15eb3a52bb
hex963621d1

2520130001 has 4 divisors (see below), whose sum is σ = 2520356352. Its totient is φ = 2519903652.

The previous prime is 2520129973. The next prime is 2520130043. The reversal of 2520130001 is 1000310252.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2520130001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2520130061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95561 + ... + 119046.

It is an arithmetic number, because the mean of its divisors is an integer number (630089088).

Almost surely, 22520130001 is an apocalyptic number.

It is an amenable number.

2520130001 is a deficient number, since it is larger than the sum of its proper divisors (226351).

2520130001 is a wasteful number, since it uses less digits than its factorization.

2520130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 226350.

The product of its (nonzero) digits is 60, while the sum is 14.

The square root of 2520130001 is about 50200.8964162992. The cubic root of 2520130001 is about 1360.8418232851.

Adding to 2520130001 its reverse (1000310252), we get a palindrome (3520440253).

The spelling of 2520130001 in words is "two billion, five hundred twenty million, one hundred thirty thousand, one".

Divisors: 1 11743 214607 2520130001