Base | Representation |
---|---|
bin | 111001010011100001101100… |
… | …100110110001110100001111 |
3 | 1020001100212210002110212011001 |
4 | 321103201230212301310033 |
5 | 231013231432234043002 |
6 | 2252005114213441131 |
7 | 104041413546044446 |
oct | 7123415446616417 |
9 | 1201325702425131 |
10 | 252030503034127 |
11 | 733395995a5234 |
12 | 243252496401a7 |
13 | aa824b38b642c |
14 | 46344acc6bd5d |
15 | 1e20d59a6ca87 |
hex | e5386c9b1d0f |
252030503034127 has 2 divisors, whose sum is σ = 252030503034128. Its totient is φ = 252030503034126.
The previous prime is 252030503034049. The next prime is 252030503034131. The reversal of 252030503034127 is 721430305030252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252030503034127 - 27 = 252030503033999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252030503034197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126015251517063 + 126015251517064.
It is an arithmetic number, because the mean of its divisors is an integer number (126015251517064).
Almost surely, 2252030503034127 is an apocalyptic number.
252030503034127 is a deficient number, since it is larger than the sum of its proper divisors (1).
252030503034127 is an equidigital number, since it uses as much as digits as its factorization.
252030503034127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151200, while the sum is 37.
Adding to 252030503034127 its reverse (721430305030252), we get a palindrome (973460808064379).
The spelling of 252030503034127 in words is "two hundred fifty-two trillion, thirty billion, five hundred three million, thirty-four thousand, one hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •