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2520316147 = 17148253891
BaseRepresentation
bin1001011000111000…
…1111100011110011
320111122102022210111
42112032033203303
520130200104042
61054031042151
7116312222326
oct22616174363
96448368714
102520316147
11108371a908
125a4070357
133121c373b
1419ca1c7bd
15eb3e0517
hex9638f8f3

2520316147 has 4 divisors (see below), whose sum is σ = 2668570056. Its totient is φ = 2372062240.

The previous prime is 2520316003. The next prime is 2520316187. The reversal of 2520316147 is 7416130252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2520316147 - 227 = 2386098419 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2520316187) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74126929 + ... + 74126962.

It is an arithmetic number, because the mean of its divisors is an integer number (667142514).

Almost surely, 22520316147 is an apocalyptic number.

2520316147 is a deficient number, since it is larger than the sum of its proper divisors (148253909).

2520316147 is a wasteful number, since it uses less digits than its factorization.

2520316147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 148253908.

The product of its (nonzero) digits is 10080, while the sum is 31.

The square root of 2520316147 is about 50202.7503927823. The cubic root of 2520316147 is about 1360.8753280415.

Adding to 2520316147 its reverse (7416130252), we get a palindrome (9936446399).

The spelling of 2520316147 in words is "two billion, five hundred twenty million, three hundred sixteen thousand, one hundred forty-seven".

Divisors: 1 17 148253891 2520316147