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25205030535253 = 191326580554487
BaseRepresentation
bin1011011101100100000001…
…11001000100000001010101
310022020120120220200222121211
411232302000321010001111
511300424400304112003
6125335010422341421
75211001103413432
oct556620071040125
9108216526628554
1025205030535253
118038436709348
1229b0aa188a871
13110aa9395753a
14631d03c54b89
152da9924b596d
hex16ec80e44055

25205030535253 has 4 divisors (see below), whose sum is σ = 26531611089760. Its totient is φ = 23878449980748.

The previous prime is 25205030535233. The next prime is 25205030535277. The reversal of 25205030535253 is 35253503050252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25205030535253 - 217 = 25205030404181 is a prime.

It is a super-2 number, since 2×252050305352532 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25205030535233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 663290277225 + ... + 663290277262.

It is an arithmetic number, because the mean of its divisors is an integer number (6632902772440).

Almost surely, 225205030535253 is an apocalyptic number.

It is an amenable number.

25205030535253 is a deficient number, since it is larger than the sum of its proper divisors (1326580554507).

25205030535253 is a wasteful number, since it uses less digits than its factorization.

25205030535253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1326580554506.

The product of its (nonzero) digits is 675000, while the sum is 40.

The spelling of 25205030535253 in words is "twenty-five trillion, two hundred five billion, thirty million, five hundred thirty-five thousand, two hundred fifty-three".

Divisors: 1 19 1326580554487 25205030535253