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25205663012017 is a prime number
BaseRepresentation
bin1011011101100101001101…
…00101110001010010110001
310022020122012222211010122011
411232302212211301102301
511300432144212341032
6125335153254442521
75211022553365135
oct556624645612261
9108218188733564
1025205663012017
118038730729514
1229b1039663441
13110ab649b4547
14631d63c533c5
152da9ccc9b247
hex16eca69714b1

25205663012017 has 2 divisors, whose sum is σ = 25205663012018. Its totient is φ = 25205663012016.

The previous prime is 25205663011999. The next prime is 25205663012059. The reversal of 25205663012017 is 71021036650252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22221645152256 + 2984017859761 = 4713984^2 + 1727431^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25205663012017 is a prime.

It is not a weakly prime, because it can be changed into another prime (25205663012077) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12602831506008 + 12602831506009.

It is an arithmetic number, because the mean of its divisors is an integer number (12602831506009).

Almost surely, 225205663012017 is an apocalyptic number.

It is an amenable number.

25205663012017 is a deficient number, since it is larger than the sum of its proper divisors (1).

25205663012017 is an equidigital number, since it uses as much as digits as its factorization.

25205663012017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 40.

Adding to 25205663012017 its reverse (71021036650252), we get a palindrome (96226699662269).

The spelling of 25205663012017 in words is "twenty-five trillion, two hundred five billion, six hundred sixty-three million, twelve thousand, seventeen".