Base | Representation |
---|---|
bin | 1110101011000000101… |
… | …0011111001000010101 |
3 | 220002121202012201221101 |
4 | 3222300022133020111 |
5 | 13112211243022013 |
6 | 311444010350101 |
7 | 24132241415062 |
oct | 3526012371025 |
9 | 802552181841 |
10 | 252063642133 |
11 | 9799939a116 |
12 | 40a2772b331 |
13 | 1aa00789c04 |
14 | c2b2915c69 |
15 | 685409d8dd |
hex | 3ab029f215 |
252063642133 has 4 divisors (see below), whose sum is σ = 255100553568. Its totient is φ = 249026730700.
The previous prime is 252063642113. The next prime is 252063642137. The reversal of 252063642133 is 331246360252.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-252063642133 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 252063642092 and 252063642101.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (252063642137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1518455593 + ... + 1518455758.
It is an arithmetic number, because the mean of its divisors is an integer number (63775138392).
Almost surely, 2252063642133 is an apocalyptic number.
It is an amenable number.
252063642133 is a deficient number, since it is larger than the sum of its proper divisors (3036911435).
252063642133 is an equidigital number, since it uses as much as digits as its factorization.
252063642133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3036911434.
The product of its (nonzero) digits is 155520, while the sum is 37.
The spelling of 252063642133 in words is "two hundred fifty-two billion, sixty-three million, six hundred forty-two thousand, one hundred thirty-three".
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