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252067117 = 793190723
BaseRepresentation
bin11110000011000…
…11110100101101
3122120022100002011
433001203310231
51004012121432
641002401221
76150351361
oct1701436455
9576270064
10252067117
1111a315835
1270500211
13402b7553
14256972a1
15171e1847
hexf063d2d

252067117 has 4 divisors (see below), whose sum is σ = 255257920. Its totient is φ = 248876316.

The previous prime is 252067073. The next prime is 252067133. The reversal of 252067117 is 711760252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 252067117 - 223 = 243678509 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252097117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1595283 + ... + 1595440.

It is an arithmetic number, because the mean of its divisors is an integer number (63814480).

Almost surely, 2252067117 is an apocalyptic number.

It is an amenable number.

252067117 is a deficient number, since it is larger than the sum of its proper divisors (3190803).

252067117 is an equidigital number, since it uses as much as digits as its factorization.

252067117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3190802.

The product of its (nonzero) digits is 5880, while the sum is 31.

The square root of 252067117 is about 15876.6217124425. The cubic root of 252067117 is about 631.6920308604.

It can be divided in two parts, 25206 and 7117, that added together give a palindrome (32323).

The spelling of 252067117 in words is "two hundred fifty-two million, sixty-seven thousand, one hundred seventeen".

Divisors: 1 79 3190723 252067117