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252111331 is a prime number
BaseRepresentation
bin11110000011011…
…10100111100011
3122120101120201201
433001232213203
51004020030311
641003342031
76150624313
oct1701564743
9576346651
10252111331
1111a345a7a
1270521917
1340301704
14256a9443
15171ee9c1
hexf06e9e3

252111331 has 2 divisors, whose sum is σ = 252111332. Its totient is φ = 252111330.

The previous prime is 252111329. The next prime is 252111397. The reversal of 252111331 is 133111252.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 252111331 - 21 = 252111329 is a prime.

It is a super-2 number, since 2×2521113312 = 127120246437183122, which contains 22 as substring.

Together with 252111329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 252111299 and 252111308.

It is not a weakly prime, because it can be changed into another prime (252111311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126055665 + 126055666.

It is an arithmetic number, because the mean of its divisors is an integer number (126055666).

Almost surely, 2252111331 is an apocalyptic number.

252111331 is a deficient number, since it is larger than the sum of its proper divisors (1).

252111331 is an equidigital number, since it uses as much as digits as its factorization.

252111331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 180, while the sum is 19.

The square root of 252111331 is about 15878.0140760739. The cubic root of 252111331 is about 631.7289628211.

Adding to 252111331 its reverse (133111252), we get a palindrome (385222583).

The spelling of 252111331 in words is "two hundred fifty-two million, one hundred eleven thousand, three hundred thirty-one".