Base | Representation |
---|---|
bin | 10111011110111000… |
… | …010011001110111011 |
3 | 2102002012211212221010 |
4 | 113132320103032323 |
5 | 403114304343100 |
6 | 15325550245003 |
7 | 1551554426205 |
oct | 273670231673 |
9 | 72065755833 |
10 | 25214137275 |
11 | a7697a5588 |
12 | 4a781b6763 |
13 | 24baa00572 |
14 | 13129a9775 |
15 | 9c88c0750 |
hex | 5dee133bb |
25214137275 has 12 divisors (see below), whose sum is σ = 41687373752. Its totient is φ = 13447539840.
The previous prime is 25214137271. The next prime is 25214137279. The reversal of 25214137275 is 57273141252.
It is an interprime number because it is at equal distance from previous prime (25214137271) and next prime (25214137279).
It is not a de Polignac number, because 25214137275 - 22 = 25214137271 is a prime.
It is a super-3 number, since 3×252141372753 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (25214137271) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 168094174 + ... + 168094323.
Almost surely, 225214137275 is an apocalyptic number.
25214137275 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
25214137275 is a deficient number, since it is larger than the sum of its proper divisors (16473236477).
25214137275 is a wasteful number, since it uses less digits than its factorization.
25214137275 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 336188510 (or 336188505 counting only the distinct ones).
The product of its digits is 117600, while the sum is 39.
The spelling of 25214137275 in words is "twenty-five billion, two hundred fourteen million, one hundred thirty-seven thousand, two hundred seventy-five".
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