Base | Representation |
---|---|
bin | 1110101011010101100… |
… | …1011000011110100001 |
3 | 220002211212101222112110 |
4 | 3222311121120132201 |
5 | 13112401231324441 |
6 | 311500424145533 |
7 | 24134355550350 |
oct | 3526531303641 |
9 | 802755358473 |
10 | 252151433121 |
11 | 97a33a01855 |
12 | 40a510082a9 |
13 | 1aa15a17543 |
14 | c2c0449997 |
15 | 685bb40b16 |
hex | 3ab56587a1 |
252151433121 has 32 divisors (see below), whose sum is σ = 404514073600. Its totient is φ = 136482563520.
The previous prime is 252151433099. The next prime is 252151433161. The reversal of 252151433121 is 121334151252.
It is a happy number.
It is not a de Polignac number, because 252151433121 - 27 = 252151432993 is a prime.
It is not an unprimeable number, because it can be changed into a prime (252151433161) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2836611 + ... + 2924151.
It is an arithmetic number, because the mean of its divisors is an integer number (12641064800).
Almost surely, 2252151433121 is an apocalyptic number.
252151433121 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
252151433121 is a deficient number, since it is larger than the sum of its proper divisors (152362640479).
252151433121 is a wasteful number, since it uses less digits than its factorization.
252151433121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94789.
The product of its digits is 7200, while the sum is 30.
Adding to 252151433121 its reverse (121334151252), we get a palindrome (373485584373).
The spelling of 252151433121 in words is "two hundred fifty-two billion, one hundred fifty-one million, four hundred thirty-three thousand, one hundred twenty-one".
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