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252313044541 is a prime number
BaseRepresentation
bin1110101011111100000…
…1111000011000111101
3220010021010111200201121
43222333001320120331
513113214114411131
6311524440110541
724141360330565
oct3527701703075
9803233450647
10252313044541
1198007154908
1240a97165451
131aa403505bc
14c2d7ab7da5
15686ae15911
hex3abf07863d

252313044541 has 2 divisors, whose sum is σ = 252313044542. Its totient is φ = 252313044540.

The previous prime is 252313044523. The next prime is 252313044569. The reversal of 252313044541 is 145440313252.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 145354612516 + 106958432025 = 381254^2 + 327045^2 .

It is a cyclic number.

It is not a de Polignac number, because 252313044541 - 29 = 252313044029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 252313044497 and 252313044506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (252313044521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126156522270 + 126156522271.

It is an arithmetic number, because the mean of its divisors is an integer number (126156522271).

Almost surely, 2252313044541 is an apocalyptic number.

It is an amenable number.

252313044541 is a deficient number, since it is larger than the sum of its proper divisors (1).

252313044541 is an equidigital number, since it uses as much as digits as its factorization.

252313044541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 57600, while the sum is 34.

Adding to 252313044541 its reverse (145440313252), we get a palindrome (397753357793).

The spelling of 252313044541 in words is "two hundred fifty-two billion, three hundred thirteen million, forty-four thousand, five hundred forty-one".