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252314903 = 1453173651
BaseRepresentation
bin11110000101000…
…00010100010111
3122120202220222102
433002200110113
51004043034103
641011552315
76152432651
oct1702402427
9576686872
10252314903
1111a474a15
12705bb69b
1340373279
142571d6d1
151723ee88
hexf0a0517

252314903 has 4 divisors (see below), whose sum is σ = 252490008. Its totient is φ = 252139800.

The previous prime is 252314747. The next prime is 252314957. The reversal of 252314903 is 309413252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 252314903 - 210 = 252313879 is a prime.

It is a super-5 number, since 5×2523149035 (a number of 43 digits) contains 55555 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252314003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85373 + ... + 88278.

It is an arithmetic number, because the mean of its divisors is an integer number (63122502).

Almost surely, 2252314903 is an apocalyptic number.

252314903 is a deficient number, since it is larger than the sum of its proper divisors (175105).

252314903 is a wasteful number, since it uses less digits than its factorization.

252314903 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175104.

The product of its (nonzero) digits is 6480, while the sum is 29.

The square root of 252314903 is about 15884.4232819451. The cubic root of 252314903 is about 631.8989508568.

The spelling of 252314903 in words is "two hundred fifty-two million, three hundred fourteen thousand, nine hundred three".

Divisors: 1 1453 173651 252314903