Base | Representation |
---|---|
bin | 10111100000000100… |
… | …000100100010101001 |
3 | 2102010121020000112010 |
4 | 113200010010202221 |
5 | 403134401000131 |
6 | 15331540110133 |
7 | 1552215314145 |
oct | 274004044251 |
9 | 72117200463 |
10 | 25234000041 |
11 | a779a31798 |
12 | 4a82995349 |
13 | 24c1b66393 |
14 | 131549a225 |
15 | 9ca4e5b46 |
hex | 5e01048a9 |
25234000041 has 4 divisors (see below), whose sum is σ = 33645333392. Its totient is φ = 16822666692.
The previous prime is 25234000003. The next prime is 25234000049. The reversal of 25234000041 is 14000043252.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 25234000041 - 215 = 25233967273 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 25233999981 and 25234000017.
It is not an unprimeable number, because it can be changed into a prime (25234000049) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4205666671 + ... + 4205666676.
It is an arithmetic number, because the mean of its divisors is an integer number (8411333348).
Almost surely, 225234000041 is an apocalyptic number.
It is an amenable number.
25234000041 is a deficient number, since it is larger than the sum of its proper divisors (8411333351).
25234000041 is an equidigital number, since it uses as much as digits as its factorization.
25234000041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8411333350.
The product of its (nonzero) digits is 960, while the sum is 21.
Adding to 25234000041 its reverse (14000043252), we get a palindrome (39234043293).
The spelling of 25234000041 in words is "twenty-five billion, two hundred thirty-four million, forty-one", and thus it is an aban number.
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