403134401000131 has 4 divisors (see below), whose sum is σ = 408812350310064. Its totient is φ = 397456451690200.

The previous prime is 403134401000119. The next prime is 403134401000147. The reversal of 403134401000131 is 131000104431304.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 403134401000131 - 2²¹ = 403134398902979 is a prime.

It is a super-2 number, since 2×403134401000131² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 403134401000096 and 403134401000105.

It is not an unprimeable number, because it can be changed into a prime (403134401000101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2838974654860 + ... + 2838974655001.

It is an arithmetic number, because the mean of its divisors is an integer number (102203087577516).

Almost surely, 2^{403134401000131} is an apocalyptic number.

403134401000131 is a deficient number, since it is larger than the sum of its proper divisors (5677949309933).

403134401000131 is an equidigital number, since it uses as much as digits as its factorization.

403134401000131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5677949309932.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 403134401000131 its reverse (131000104431304), we get a palindrome (534134505431435).

The spelling of 403134401000131 in words is "four hundred three trillion, one hundred thirty-four billion, four hundred one million, one hundred thirty-one", and thus it is an aban number.