Base | Representation |
---|---|
bin | 111001011001000100100100… |
… | …011000011011101101111111 |
3 | 1020002201022022110011012020002 |
4 | 321121010210120123231333 |
5 | 231041002320102402031 |
6 | 2252500132351144515 |
7 | 104111063230536221 |
oct | 7131044430335577 |
9 | 1202638273135202 |
10 | 252411543403391 |
11 | 73476152994419 |
12 | 2438706b21513b |
13 | aaac3ca24c958 |
14 | 4648ad8da4411 |
15 | 1e2ac0bc02ccb |
hex | e5912461bb7f |
252411543403391 has 2 divisors, whose sum is σ = 252411543403392. Its totient is φ = 252411543403390.
The previous prime is 252411543403309. The next prime is 252411543403451. The reversal of 252411543403391 is 193304345114252.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-252411543403391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252411543402391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126205771701695 + 126205771701696.
It is an arithmetic number, because the mean of its divisors is an integer number (126205771701696).
Almost surely, 2252411543403391 is an apocalyptic number.
252411543403391 is a deficient number, since it is larger than the sum of its proper divisors (1).
252411543403391 is an equidigital number, since it uses as much as digits as its factorization.
252411543403391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 47.
The spelling of 252411543403391 in words is "two hundred fifty-two trillion, four hundred eleven billion, five hundred forty-three million, four hundred three thousand, three hundred ninety-one".
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