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252416398317 = 384138799439
BaseRepresentation
bin1110101100010100110…
…0001001001111101101
3220010112022222121110020
43223011030021033231
513113422044221232
6311543011232353
724144053661546
oct3530514111755
9803468877406
10252416398317
119805a527056
1240b058a86b9
131aa58899795
14c3076dd4cd
15687502de2c
hex3ac53093ed

252416398317 has 4 divisors (see below), whose sum is σ = 336555197760. Its totient is φ = 168277598876.

The previous prime is 252416398307. The next prime is 252416398319. The reversal of 252416398317 is 713893614252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 252416398317 - 218 = 252416136173 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 252416398317.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252416398319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42069399717 + ... + 42069399722.

It is an arithmetic number, because the mean of its divisors is an integer number (84138799440).

Almost surely, 2252416398317 is an apocalyptic number.

It is an amenable number.

252416398317 is a deficient number, since it is larger than the sum of its proper divisors (84138799443).

252416398317 is an equidigital number, since it uses as much as digits as its factorization.

252416398317 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 84138799442.

The product of its digits is 2177280, while the sum is 51.

The spelling of 252416398317 in words is "two hundred fifty-two billion, four hundred sixteen million, three hundred ninety-eight thousand, three hundred seventeen".

Divisors: 1 3 84138799439 252416398317