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25250528437 is a prime number
BaseRepresentation
bin10111100001000011…
…000111110010110101
32102011202022202012221
4113201003013302311
5403203113402222
615333330242341
71552505643661
oct274103076265
972152282187
1025250528437
11a7882a0822
124a884263b1
1324c54025b4
14131775d8a1
159cbbad0c7
hex5e10c7cb5

25250528437 has 2 divisors, whose sum is σ = 25250528438. Its totient is φ = 25250528436.

The previous prime is 25250528419. The next prime is 25250528447. The reversal of 25250528437 is 73482505252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18710409796 + 6540118641 = 136786^2 + 80871^2 .

It is a cyclic number.

It is not a de Polignac number, because 25250528437 - 27 = 25250528309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25250528393 and 25250528402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25250528447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12625264218 + 12625264219.

It is an arithmetic number, because the mean of its divisors is an integer number (12625264219).

Almost surely, 225250528437 is an apocalyptic number.

It is an amenable number.

25250528437 is a deficient number, since it is larger than the sum of its proper divisors (1).

25250528437 is an equidigital number, since it uses as much as digits as its factorization.

25250528437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672000, while the sum is 43.

The spelling of 25250528437 in words is "twenty-five billion, two hundred fifty million, five hundred twenty-eight thousand, four hundred thirty-seven".