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252541454142319 is a prime number
BaseRepresentation
bin111001011010111101100011…
…101010100100101101101111
31020010011201122011010111200021
4321122331203222210231233
5231100114344230023234
62253035535321143011
7104123342441566216
oct7132754352445557
91203151564114607
10252541454142319
1173516258137371
12243a828602aa67
13aabb7317a0984
14465110067607d
151e2e2b1cd39b4
hexe5af63aa4b6f

252541454142319 has 2 divisors, whose sum is σ = 252541454142320. Its totient is φ = 252541454142318.

The previous prime is 252541454142199. The next prime is 252541454142331. The reversal of 252541454142319 is 913241454145252.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 252541454142319 - 211 = 252541454140271 is a prime.

It is a super-3 number, since 3×2525414541423193 (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (252541454142379) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126270727071159 + 126270727071160.

It is an arithmetic number, because the mean of its divisors is an integer number (126270727071160).

Almost surely, 2252541454142319 is an apocalyptic number.

252541454142319 is a deficient number, since it is larger than the sum of its proper divisors (1).

252541454142319 is an equidigital number, since it uses as much as digits as its factorization.

252541454142319 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912000, while the sum is 52.

The spelling of 252541454142319 in words is "two hundred fifty-two trillion, five hundred forty-one billion, four hundred fifty-four million, one hundred forty-two thousand, three hundred nineteen".