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2525440651141 = 7931967603179
BaseRepresentation
bin100100101111111111111…
…111100010111110000101
322221102121022010112202011
4210233333333202332011
5312334100301314031
65212101005414221
7350312526230122
oct44577777427605
98842538115664
102525440651141
11894040456001
12349544b6a371
131541c02c0c75
148a3367a3749
1545a5c3266b1
hex24bfffe2f85

2525440651141 has 4 divisors (see below), whose sum is σ = 2557408254400. Its totient is φ = 2493473047884.

The previous prime is 2525440651109. The next prime is 2525440651187. The reversal of 2525440651141 is 1411560445252.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2525440651141 - 25 = 2525440651109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2525440651094 and 2525440651103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2525440651241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15983801511 + ... + 15983801668.

It is an arithmetic number, because the mean of its divisors is an integer number (639352063600).

Almost surely, 22525440651141 is an apocalyptic number.

It is an amenable number.

2525440651141 is a deficient number, since it is larger than the sum of its proper divisors (31967603259).

2525440651141 is an equidigital number, since it uses as much as digits as its factorization.

2525440651141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31967603258.

The product of its (nonzero) digits is 192000, while the sum is 40.

The spelling of 2525440651141 in words is "two trillion, five hundred twenty-five billion, four hundred forty million, six hundred fifty-one thousand, one hundred forty-one".

Divisors: 1 79 31967603179 2525440651141