Base | Representation |
---|---|
bin | 100100110000000000100… |
… | …110101100010101101011 |
3 | 22221102122000102220112212 |
4 | 210300000212230111223 |
5 | 312334110413210011 |
6 | 5212102013355335 |
7 | 350313012400346 |
oct | 44600046542553 |
9 | 8842560386485 |
10 | 2525450913131 |
11 | 894046224a93 |
12 | 349548498b4b |
13 | 1541c2474b53 |
14 | 8a337cb545d |
15 | 45a5d1a208b |
hex | 24c009ac56b |
2525450913131 has 2 divisors, whose sum is σ = 2525450913132. Its totient is φ = 2525450913130.
The previous prime is 2525450913079. The next prime is 2525450913157. The reversal of 2525450913131 is 1313190545252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2525450913131 - 214 = 2525450896747 is a prime.
It is a super-2 number, since 2×25254509131312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2525450913331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1262725456565 + 1262725456566.
It is an arithmetic number, because the mean of its divisors is an integer number (1262725456566).
Almost surely, 22525450913131 is an apocalyptic number.
2525450913131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2525450913131 is an equidigital number, since it uses as much as digits as its factorization.
2525450913131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 41.
The spelling of 2525450913131 in words is "two trillion, five hundred twenty-five billion, four hundred fifty million, nine hundred thirteen thousand, one hundred thirty-one".
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