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252551326051231 = 614140185672971
BaseRepresentation
bin111001011011000110110000…
…000100111010101110011111
31020010012200010010212102212021
4321123012300010322232133
5231100300103432114411
62253044251050321011
7104124142202460604
oct7133066004725637
91203180103772767
10252551326051231
117351a463613679
12243aa180129167
13aabc645a904ac
1446517997b46ab
151e2e68d7dda71
hexe5b1b013ab9f

252551326051231 has 4 divisors (see below), whose sum is σ = 256691511724264. Its totient is φ = 248411140378200.

The previous prime is 252551326051051. The next prime is 252551326051237. The reversal of 252551326051231 is 132150623155252.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-252551326051231 is a prime.

It is a super-2 number, since 2×2525513260512312 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (252551326051237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2070092836425 + ... + 2070092836546.

It is an arithmetic number, because the mean of its divisors is an integer number (64172877931066).

Almost surely, 2252551326051231 is an apocalyptic number.

252551326051231 is a deficient number, since it is larger than the sum of its proper divisors (4140185673033).

252551326051231 is an equidigital number, since it uses as much as digits as its factorization.

252551326051231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4140185673032.

The product of its (nonzero) digits is 540000, while the sum is 43.

The spelling of 252551326051231 in words is "two hundred fifty-two trillion, five hundred fifty-one billion, three hundred twenty-six million, fifty-one thousand, two hundred thirty-one".

Divisors: 1 61 4140185672971 252551326051231