Base | Representation |
---|---|
bin | 1110101101001110111… |
… | …1000100010001010011 |
3 | 220011011100011220110222 |
4 | 3223103233010101103 |
5 | 13114422032342003 |
6 | 312023125543255 |
7 | 24153106153055 |
oct | 3532357042123 |
9 | 804140156428 |
10 | 252660434003 |
11 | 9817525673a |
12 | 40b73574b2b |
13 | 1aa973014b3 |
14 | c32bca58d5 |
15 | 688b685c38 |
hex | 3ad3bc4453 |
252660434003 has 4 divisors (see below), whose sum is σ = 263645670288. Its totient is φ = 241675197720.
The previous prime is 252660433937. The next prime is 252660434017. The reversal of 252660434003 is 300434066252.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 252660434003 - 212 = 252660429907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (252660434063) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5492618108 + ... + 5492618153.
It is an arithmetic number, because the mean of its divisors is an integer number (65911417572).
Almost surely, 2252660434003 is an apocalyptic number.
252660434003 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
252660434003 is a deficient number, since it is larger than the sum of its proper divisors (10985236285).
252660434003 is a wasteful number, since it uses less digits than its factorization.
252660434003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10985236284.
The product of its (nonzero) digits is 103680, while the sum is 35.
The spelling of 252660434003 in words is "two hundred fifty-two billion, six hundred sixty million, four hundred thirty-four thousand, three".
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