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252943841 is a prime number
BaseRepresentation
bin11110001001110…
…01110111100001
3122121221212201102
433010321313201
51004223200331
641033244145
76160662413
oct1704716741
9577855642
10252943841
1111a8644a7
1270863655
1340533617
14258449b3
15173164cb
hexf139de1

252943841 has 2 divisors, whose sum is σ = 252943842. Its totient is φ = 252943840.

The previous prime is 252943807. The next prime is 252943843. The reversal of 252943841 is 148349252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 234702400 + 18241441 = 15320^2 + 4271^2 .

It is a cyclic number.

It is not a de Polignac number, because 252943841 - 222 = 248749537 is a prime.

Together with 252943843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 252943795 and 252943804.

It is not a weakly prime, because it can be changed into another prime (252943843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126471920 + 126471921.

It is an arithmetic number, because the mean of its divisors is an integer number (126471921).

Almost surely, 2252943841 is an apocalyptic number.

It is an amenable number.

252943841 is a deficient number, since it is larger than the sum of its proper divisors (1).

252943841 is an equidigital number, since it uses as much as digits as its factorization.

252943841 is an evil number, because the sum of its binary digits is even.

The product of its digits is 69120, while the sum is 38.

The square root of 252943841 is about 15904.2082795718. The cubic root of 252943841 is about 632.4235539056.

The spelling of 252943841 in words is "two hundred fifty-two million, nine hundred forty-three thousand, eight hundred forty-one".