Base | Representation |
---|---|
bin | 100100110100010001110… |
… | …110001000111101100101 |
3 | 22221212110111110220000211 |
4 | 210310101312020331211 |
5 | 312423002444030001 |
6 | 5214140533335421 |
7 | 350534425610506 |
oct | 44642166107545 |
9 | 8855414426024 |
10 | 2530035142501 |
11 | 895a889753a9 |
12 | 34a407797571 |
13 | 15477312cac9 |
14 | 8a650a68bad |
15 | 45c2a87c351 |
hex | 24d11d88f65 |
2530035142501 has 2 divisors, whose sum is σ = 2530035142502. Its totient is φ = 2530035142500.
The previous prime is 2530035142493. The next prime is 2530035142559. The reversal of 2530035142501 is 1052415300352.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2486531611876 + 43503530625 = 1576874^2 + 208575^2 .
It is a cyclic number.
It is not a de Polignac number, because 2530035142501 - 23 = 2530035142493 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2530035142601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265017571250 + 1265017571251.
It is an arithmetic number, because the mean of its divisors is an integer number (1265017571251).
Almost surely, 22530035142501 is an apocalyptic number.
It is an amenable number.
2530035142501 is a deficient number, since it is larger than the sum of its proper divisors (1).
2530035142501 is an equidigital number, since it uses as much as digits as its factorization.
2530035142501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 2530035142501 in words is "two trillion, five hundred thirty billion, thirty-five million, one hundred forty-two thousand, five hundred one".
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