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2530113441 = 3843371147
BaseRepresentation
bin1001011011001110…
…0111011110100001
320112022212002011020
42112303213132201
520140202112231
61055021040053
7116461416012
oct22663473641
96468762136
102530113441
111089201749
125a73b6029
13314243c5b
141a004d009
15ec1c8396
hex96ce77a1

2530113441 has 4 divisors (see below), whose sum is σ = 3373484592. Its totient is φ = 1686742292.

The previous prime is 2530113427. The next prime is 2530113457. The reversal of 2530113441 is 1443110352.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2530113441 - 230 = 1456371617 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2530113401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 421685571 + ... + 421685576.

It is an arithmetic number, because the mean of its divisors is an integer number (843371148).

Almost surely, 22530113441 is an apocalyptic number.

It is an amenable number.

2530113441 is a deficient number, since it is larger than the sum of its proper divisors (843371151).

2530113441 is an equidigital number, since it uses as much as digits as its factorization.

2530113441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 843371150.

The product of its (nonzero) digits is 1440, while the sum is 24.

The square root of 2530113441 is about 50300.2330113887. The cubic root of 2530113441 is about 1362.6364373204.

Adding to 2530113441 its reverse (1443110352), we get a palindrome (3973223793).

The spelling of 2530113441 in words is "two billion, five hundred thirty million, one hundred thirteen thousand, four hundred forty-one".

Divisors: 1 3 843371147 2530113441