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2530113441442 = 21265056720721
BaseRepresentation
bin100100110100010110100…
…000110100111010100010
322221212122221210212222121
4210310112200310322202
5312423133020111232
65214152411454454
7350536366260346
oct44642640647242
98855587725877
102530113441442
11896019094574
1234a429a5742a
13154786415b42
148a65b20b626
1545c32696d97
hex24d16834ea2

2530113441442 has 4 divisors (see below), whose sum is σ = 3795170162166. Its totient is φ = 1265056720720.

The previous prime is 2530113441409. The next prime is 2530113441467. The reversal of 2530113441442 is 2441443110352.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2154968216361 + 375145225081 = 1467981^2 + 612491^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2530113441398 and 2530113441407.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 632528360359 + ... + 632528360362.

Almost surely, 22530113441442 is an apocalyptic number.

2530113441442 is a deficient number, since it is larger than the sum of its proper divisors (1265056720724).

2530113441442 is a wasteful number, since it uses less digits than its factorization.

2530113441442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1265056720723.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 2530113441442 its reverse (2441443110352), we get a palindrome (4971556551794).

The spelling of 2530113441442 in words is "two trillion, five hundred thirty billion, one hundred thirteen million, four hundred forty-one thousand, four hundred forty-two".

Divisors: 1 2 1265056720721 2530113441442