Base | Representation |
---|---|
bin | 100100110100010110100… |
… | …000110100111010100011 |
3 | 22221212122221210212222122 |
4 | 210310112200310322203 |
5 | 312423133020111233 |
6 | 5214152411454455 |
7 | 350536366260350 |
oct | 44642640647243 |
9 | 8855587725878 |
10 | 2530113441443 |
11 | 896019094575 |
12 | 34a429a5742b |
13 | 154786415b43 |
14 | 8a65b20b627 |
15 | 45c32696d98 |
hex | 24d16834ea3 |
2530113441443 has 8 divisors (see below), whose sum is σ = 2891568119040. Its totient is φ = 2168661238920.
The previous prime is 2530113441409. The next prime is 2530113441467. The reversal of 2530113441443 is 3441443110352.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2530113441443 - 210 = 2530113440419 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2530113441473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2924168 + ... + 3689306.
It is an arithmetic number, because the mean of its divisors is an integer number (361446014880).
Almost surely, 22530113441443 is an apocalyptic number.
2530113441443 is a deficient number, since it is larger than the sum of its proper divisors (361454677597).
2530113441443 is an equidigital number, since it uses as much as digits as its factorization.
2530113441443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1237537.
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 2530113441443 its reverse (3441443110352), we get a palindrome (5971556551795).
The spelling of 2530113441443 in words is "two trillion, five hundred thirty billion, one hundred thirteen million, four hundred forty-one thousand, four hundred forty-three".
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