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2530114433 = 71142178049
BaseRepresentation
bin1001011011001110…
…0111101110000001
320112022212010111222
42112303213232001
520140202130213
61055021044425
7116461421630
oct22663475601
96468763458
102530114433
111089202470
125a73b6715
13314244542
141a004d517
15ec1c8808
hex96ce7b81

2530114433 has 16 divisors (see below), whose sum is σ = 3161961600. Its totient is φ = 1966809600.

The previous prime is 2530114421. The next prime is 2530114549. The reversal of 2530114433 is 3344110352.

It is not a de Polignac number, because 2530114433 - 226 = 2463005569 is a prime.

It is a super-2 number, since 2×25301144332 = 12802958088149822978, which contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (2530114733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6608 + ... + 71441.

It is an arithmetic number, because the mean of its divisors is an integer number (197622600).

Almost surely, 22530114433 is an apocalyptic number.

It is an amenable number.

2530114433 is a deficient number, since it is larger than the sum of its proper divisors (631847167).

2530114433 is a wasteful number, since it uses less digits than its factorization.

2530114433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78488.

The product of its (nonzero) digits is 4320, while the sum is 26.

The square root of 2530114433 is about 50300.2428721771. The cubic root of 2530114433 is about 1362.6366154067.

Adding to 2530114433 its reverse (3344110352), we get a palindrome (5874224785).

The spelling of 2530114433 in words is "two billion, five hundred thirty million, one hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 7 11 77 421 2947 4631 32417 78049 546343 858539 6009773 32858629 230010403 361444919 2530114433