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2530255528051 is a prime number
BaseRepresentation
bin100100110100011110111…
…110110110000001110011
322221220000212011122011121
4210310132332312001303
5312423430403344201
65214214445123111
7350543043061126
oct44643676660163
98856025148147
102530255528051
11896091311319
1234a469559497
131547a99a3b64
148a6720363bd
1545c3edb19a1
hex24d1efb6073

2530255528051 has 2 divisors, whose sum is σ = 2530255528052. Its totient is φ = 2530255528050.

The previous prime is 2530255528019. The next prime is 2530255528079. The reversal of 2530255528051 is 1508255520352.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2530255528051 - 25 = 2530255528019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2530255527989 and 2530255528007.

It is not a weakly prime, because it can be changed into another prime (2530255528351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265127764025 + 1265127764026.

It is an arithmetic number, because the mean of its divisors is an integer number (1265127764026).

Almost surely, 22530255528051 is an apocalyptic number.

2530255528051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2530255528051 is an equidigital number, since it uses as much as digits as its factorization.

2530255528051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 600000, while the sum is 43.

The spelling of 2530255528051 in words is "two trillion, five hundred thirty billion, two hundred fifty-five million, five hundred twenty-eight thousand, fifty-one".