Base | Representation |
---|---|
bin | 1001011011010001… |
… | …0000011100010011 |
3 | 20112100011121022211 |
4 | 2112310100130103 |
5 | 20140222444420 |
6 | 1055024412551 |
7 | 116463015136 |
oct | 22664203423 |
9 | 6470147284 |
10 | 2530281235 |
11 | 1089306819 |
12 | 5a7477157 |
13 | 3142a2441 |
14 | 1a009421d |
15 | ec20ce5a |
hex | 96d10713 |
2530281235 has 4 divisors (see below), whose sum is σ = 3036337488. Its totient is φ = 2024224984.
The previous prime is 2530281217. The next prime is 2530281239. The reversal of 2530281235 is 5321820352.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2530281235 - 27 = 2530281107 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2530281197 and 2530281206.
It is not an unprimeable number, because it can be changed into a prime (2530281239) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253028119 + ... + 253028128.
It is an arithmetic number, because the mean of its divisors is an integer number (759084372).
Almost surely, 22530281235 is an apocalyptic number.
2530281235 is a deficient number, since it is larger than the sum of its proper divisors (506056253).
2530281235 is an equidigital number, since it uses as much as digits as its factorization.
2530281235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506056252.
The product of its (nonzero) digits is 14400, while the sum is 31.
The square root of 2530281235 is about 50301.9009084150. The cubic root of 2530281235 is about 1362.6665594433. Note that the first 3 decimals are identical.
The spelling of 2530281235 in words is "two billion, five hundred thirty million, two hundred eighty-one thousand, two hundred thirty-five".
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