Base | Representation |
---|---|
bin | 1110101110101001101… |
… | …1011001010000001011 |
3 | 220012010212120102210212 |
4 | 3223222123121100023 |
5 | 13121212013344120 |
6 | 312125010031335 |
7 | 24165411212066 |
oct | 3535233312013 |
9 | 805125512725 |
10 | 253041153035 |
11 | 98350152570 |
12 | 4105ab7854b |
13 | 1ab28151a28 |
14 | c36668b8dd |
15 | 68aecdb6c5 |
hex | 3aea6d940b |
253041153035 has 16 divisors (see below), whose sum is σ = 331274119680. Its totient is φ = 184018681440.
The previous prime is 253041152983. The next prime is 253041153041. The reversal of 253041153035 is 530351140352.
It is not a de Polignac number, because 253041153035 - 214 = 253041136651 is a prime.
It is a super-2 number, since 2×2530411530352 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 253041152992 and 253041153010.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 827486 + ... + 1091244.
It is an arithmetic number, because the mean of its divisors is an integer number (20704632480).
Almost surely, 2253041153035 is an apocalyptic number.
253041153035 is a deficient number, since it is larger than the sum of its proper divisors (78232966645).
253041153035 is a wasteful number, since it uses less digits than its factorization.
253041153035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 281218.
The product of its (nonzero) digits is 27000, while the sum is 32.
Adding to 253041153035 its reverse (530351140352), we get a palindrome (783392293387).
The spelling of 253041153035 in words is "two hundred fifty-three billion, forty-one million, one hundred fifty-three thousand, thirty-five".
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