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25308864197 is a prime number
BaseRepresentation
bin10111100100100001…
…101001111011000101
32102022211002111211122
4113210201221323011
5403313032123242
615343212443325
71554114540041
oct274441517305
972284074748
1025308864197
11a8082152a1
124aa3a79545
132504518bb6
1413213c7021
159d1d82ad2
hex5e4869ec5

25308864197 has 2 divisors, whose sum is σ = 25308864198. Its totient is φ = 25308864196.

The previous prime is 25308864181. The next prime is 25308864221. The reversal of 25308864197 is 79146880352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21683740516 + 3625123681 = 147254^2 + 60209^2 .

It is a cyclic number.

It is not a de Polignac number, because 25308864197 - 24 = 25308864181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25308864107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12654432098 + 12654432099.

It is an arithmetic number, because the mean of its divisors is an integer number (12654432099).

It is a 2-persistent number, because it is pandigital, and so is 2⋅25308864197 = 50617728394, but 3⋅25308864197 = 75926592591 is not.

Almost surely, 225308864197 is an apocalyptic number.

It is an amenable number.

25308864197 is a deficient number, since it is larger than the sum of its proper divisors (1).

25308864197 is an equidigital number, since it uses as much as digits as its factorization.

25308864197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2903040, while the sum is 53.

The spelling of 25308864197 in words is "twenty-five billion, three hundred eight million, eight hundred sixty-four thousand, one hundred ninety-seven".