253134101431333 has 2 divisors, whose sum is σ = 253134101431334. Its totient is φ = 253134101431332.

The previous prime is 253134101431327. The next prime is 253134101431363. The reversal of 253134101431333 is 333134101431352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206947846605124 + 46186254826209 = 14385682^2 + 6796047^2 .

It is a cyclic number.

It is not a de Polignac number, because 253134101431333 - 2¹⁷ = 253134101300261 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253134101431292 and 253134101431301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253134101431363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126567050715666 + 126567050715667.

It is an arithmetic number, because the mean of its divisors is an integer number (126567050715667).

Almost surely, 2^{253134101431333} is an apocalyptic number.

It is an amenable number.

253134101431333 is a deficient number, since it is larger than the sum of its proper divisors (1).

253134101431333 is an equidigital number, since it uses as much as digits as its factorization.

253134101431333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 37.

Adding to 253134101431333 its reverse (333134101431352), we get a palindrome (586268202862685).

The spelling of 253134101431333 in words is "two hundred fifty-three trillion, one hundred thirty-four billion, one hundred one million, four hundred thirty-one thousand, three hundred thirty-three".