Base | Representation |
---|---|
bin | 111001100011100101100000… |
… | …001100100100010000111001 |
3 | 1020012021101100202120010220010 |
4 | 321203211200030210100321 |
5 | 231134322114431300403 |
6 | 2254212111213252133 |
7 | 104214223003460142 |
oct | 7143454014442071 |
9 | 1205241322503803 |
10 | 253134101431353 |
11 | 7372462a07a32a |
12 | 24483102494049 |
13 | ab3259c03011c |
14 | 4671a821c8ac9 |
15 | 1e3e8eb3b5603 |
hex | e63960324439 |
253134101431353 has 16 divisors (see below), whose sum is σ = 345787100992256. Its totient is φ = 164628263071440.
The previous prime is 253134101431333. The next prime is 253134101431363. The reversal of 253134101431353 is 353134101431352.
It is not a de Polignac number, because 253134101431353 - 29 = 253134101430841 is a prime.
It is not an unprimeable number, because it can be changed into a prime (253134101431333) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1209685675 + ... + 1209894912.
It is an arithmetic number, because the mean of its divisors is an integer number (21611693812016).
Almost surely, 2253134101431353 is an apocalyptic number.
It is an amenable number.
253134101431353 is a deficient number, since it is larger than the sum of its proper divisors (92652999560903).
253134101431353 is a wasteful number, since it uses less digits than its factorization.
253134101431353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2419581444.
The product of its (nonzero) digits is 194400, while the sum is 39.
Subtracting 253134101431353 from its reverse (353134101431352), we obtain a palindrome (99999999999999).
The spelling of 253134101431353 in words is "two hundred fifty-three trillion, one hundred thirty-four billion, one hundred one million, four hundred thirty-one thousand, three hundred fifty-three".
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