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253160113283111 is a prime number
BaseRepresentation
bin111001100011111101101110…
…100111111010000000100111
31020012100212111120110010101002
4321203331232213322000213
5231140233403000024421
62254232052301423515
7104216133415533506
oct7143755647720047
91205325446403332
10253160113283111
1173734668094581
122448816186ab9b
13ab34b86093198
14467302cac683d
151e4041ed0ab0b
hexe63f6e9fa027

253160113283111 has 2 divisors, whose sum is σ = 253160113283112. Its totient is φ = 253160113283110.

The previous prime is 253160113283071. The next prime is 253160113283137. The reversal of 253160113283111 is 111382311061352.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 253160113283111 - 218 = 253160113020967 is a prime.

It is a super-3 number, since 3×2531601132831113 (a number of 44 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253160113283171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126580056641555 + 126580056641556.

It is an arithmetic number, because the mean of its divisors is an integer number (126580056641556).

Almost surely, 2253160113283111 is an apocalyptic number.

253160113283111 is a deficient number, since it is larger than the sum of its proper divisors (1).

253160113283111 is an equidigital number, since it uses as much as digits as its factorization.

253160113283111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 38.

The spelling of 253160113283111 in words is "two hundred fifty-three trillion, one hundred sixty billion, one hundred thirteen million, two hundred eighty-three thousand, one hundred eleven".