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253195477313 is a prime number
BaseRepresentation
bin1110101111001110100…
…0000110000101000001
3220012112121221220220212
43223303220012011001
513122021020233223
6312152201443505
724202264022102
oct3536350060501
9805477856825
10253195477313
119841a278699
12410a27a0595
131ab51105c7c
14c37cd803a9
1568bd622278
hex3af3a06141

253195477313 has 2 divisors, whose sum is σ = 253195477314. Its totient is φ = 253195477312.

The previous prime is 253195477247. The next prime is 253195477343. The reversal of 253195477313 is 313774591352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 156015520144 + 97179957169 = 394988^2 + 311737^2 .

It is a cyclic number.

It is not a de Polignac number, because 253195477313 - 224 = 253178700097 is a prime.

It is not a weakly prime, because it can be changed into another prime (253195477343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126597738656 + 126597738657.

It is an arithmetic number, because the mean of its divisors is an integer number (126597738657).

Almost surely, 2253195477313 is an apocalyptic number.

It is an amenable number.

253195477313 is a deficient number, since it is larger than the sum of its proper divisors (1).

253195477313 is an equidigital number, since it uses as much as digits as its factorization.

253195477313 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2381400, while the sum is 50.

The spelling of 253195477313 in words is "two hundred fifty-three billion, one hundred ninety-five million, four hundred seventy-seven thousand, three hundred thirteen".