Base | Representation |
---|---|
bin | 1110101111001111101… |
… | …0101010011111001011 |
3 | 220012112222010020011212 |
4 | 3223303322222133023 |
5 | 13122023242020120 |
6 | 312152454043335 |
7 | 24202353264521 |
oct | 3536372523713 |
9 | 805488106155 |
10 | 253200345035 |
11 | 98421aa2900 |
12 | 410a434954b |
13 | 1ab5211b791 |
14 | c37d88a311 |
15 | 68bdc846c5 |
hex | 3af3eaa7cb |
253200345035 has 12 divisors (see below), whose sum is σ = 333973348464. Its totient is φ = 184145705040.
The previous prime is 253200345017. The next prime is 253200345059. The reversal of 253200345035 is 530543002352.
It is not a de Polignac number, because 253200345035 - 222 = 253196150731 is a prime.
It is a super-2 number, since 2×2532003450352 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 253200344992 and 253200345010.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 209255879 + ... + 209257088.
It is an arithmetic number, because the mean of its divisors is an integer number (27831112372).
Almost surely, 2253200345035 is an apocalyptic number.
253200345035 is a deficient number, since it is larger than the sum of its proper divisors (80773003429).
253200345035 is a wasteful number, since it uses less digits than its factorization.
253200345035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 418512994 (or 418512983 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 32.
Adding to 253200345035 its reverse (530543002352), we get a palindrome (783743347387).
The spelling of 253200345035 in words is "two hundred fifty-three billion, two hundred million, three hundred forty-five thousand, thirty-five".
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