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253200452079 = 384400150693
BaseRepresentation
bin1110101111001111101…
…1000100100111101111
3220012112222022200000110
43223303323010213233
513122023303431304
6312152500231103
724202354221561
oct3536373044757
9805488280013
10253200452079
1198422066273
12410a439b493
131ab52158413
14c37d8b7331
1568bdca6289
hex3af3ec49ef

253200452079 has 4 divisors (see below), whose sum is σ = 337600602776. Its totient is φ = 168800301384.

The previous prime is 253200452053. The next prime is 253200452093. The reversal of 253200452079 is 970254002352.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 253200452079 - 229 = 252663581167 is a prime.

It is a super-3 number, since 3×2532004520793 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253200452009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42200075344 + ... + 42200075349.

It is an arithmetic number, because the mean of its divisors is an integer number (84400150694).

Almost surely, 2253200452079 is an apocalyptic number.

253200452079 is a deficient number, since it is larger than the sum of its proper divisors (84400150697).

253200452079 is an equidigital number, since it uses as much as digits as its factorization.

253200452079 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84400150696.

The product of its (nonzero) digits is 151200, while the sum is 39.

The spelling of 253200452079 in words is "two hundred fifty-three billion, two hundred million, four hundred fifty-two thousand, seventy-nine".

Divisors: 1 3 84400150693 253200452079