Base | Representation |
---|---|
bin | 1110101111001111101… |
… | …1000100100111101111 |
3 | 220012112222022200000110 |
4 | 3223303323010213233 |
5 | 13122023303431304 |
6 | 312152500231103 |
7 | 24202354221561 |
oct | 3536373044757 |
9 | 805488280013 |
10 | 253200452079 |
11 | 98422066273 |
12 | 410a439b493 |
13 | 1ab52158413 |
14 | c37d8b7331 |
15 | 68bdca6289 |
hex | 3af3ec49ef |
253200452079 has 4 divisors (see below), whose sum is σ = 337600602776. Its totient is φ = 168800301384.
The previous prime is 253200452053. The next prime is 253200452093. The reversal of 253200452079 is 970254002352.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 253200452079 - 229 = 252663581167 is a prime.
It is a super-3 number, since 3×2532004520793 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (253200452009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42200075344 + ... + 42200075349.
It is an arithmetic number, because the mean of its divisors is an integer number (84400150694).
Almost surely, 2253200452079 is an apocalyptic number.
253200452079 is a deficient number, since it is larger than the sum of its proper divisors (84400150697).
253200452079 is an equidigital number, since it uses as much as digits as its factorization.
253200452079 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84400150696.
The product of its (nonzero) digits is 151200, while the sum is 39.
The spelling of 253200452079 in words is "two hundred fifty-three billion, two hundred million, four hundred fifty-two thousand, seventy-nine".
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