Base | Representation |
---|---|
bin | 100100110110001100000… |
… | …010101101011011111111 |
3 | 22222001202101010112202212 |
4 | 210312030002231123333 |
5 | 312441202311223413 |
6 | 5215120210411035 |
7 | 350636301400541 |
oct | 44661402553377 |
9 | 8861671115685 |
10 | 2532085257983 |
11 | 896940131516 |
12 | 34a89a290a7b |
13 | 154a0baa2ca8 |
14 | 8a7a704b691 |
15 | 45cea83dca8 |
hex | 24d8c0ad6ff |
2532085257983 has 16 divisors (see below), whose sum is σ = 2713058167680. Its totient is φ = 2356217004384.
The previous prime is 2532085257979. The next prime is 2532085258009. The reversal of 2532085257983 is 3897525802352.
It is a cyclic number.
It is not a de Polignac number, because 2532085257983 - 22 = 2532085257979 is a prime.
It is a super-2 number, since 2×25320852579832 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2532085257683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4367741 + ... + 4913382.
It is an arithmetic number, because the mean of its divisors is an integer number (169566135480).
Almost surely, 22532085257983 is an apocalyptic number.
2532085257983 is a deficient number, since it is larger than the sum of its proper divisors (180972909697).
2532085257983 is a wasteful number, since it uses less digits than its factorization.
2532085257983 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9281398.
The product of its (nonzero) digits is 36288000, while the sum is 59.
The spelling of 2532085257983 in words is "two trillion, five hundred thirty-two billion, eighty-five million, two hundred fifty-seven thousand, nine hundred eighty-three".
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