2532347041 has 4 divisors (see below), whose sum is σ = 2894110912. Its totient is φ = 2170583172.

The previous prime is 2532347039. The next prime is 2532347089. The reversal of 2532347041 is 1407432352.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2532347041 - 2¹ = 2532347039 is a prime.

It is a super-2 number, since 2×2532347041² = 12825563072122911362, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2532346994 and 2532347012.

It is not an unprimeable number, because it can be changed into a prime (2532347011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180881925 + ... + 180881938.

It is an arithmetic number, because the mean of its divisors is an integer number (723527728).

Almost surely, 2^2532347041 is an apocalyptic number.

It is an amenable number.

2532347041 is a deficient number, since it is larger than the sum of its proper divisors (361763871).

2532347041 is an equidigital number, since it uses as much as digits as its factorization.

2532347041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 361763870.

The product of its (nonzero) digits is 20160, while the sum is 31.

The square root of 2532347041 is about 50322.4307938319. The cubic root of 2532347041 is about 1363.0373007105.

Adding to 2532347041 its reverse (1407432352), we get a palindrome (3939779393).

The spelling of 2532347041 in words is "two billion, five hundred thirty-two million, three hundred forty-seven thousand, forty-one".